December 25, 2016 in Mechanics: Statics tagged Cartesian Vector Form / Engineering Mechanics: Statics / Forces The beam is subjected to the two forces shown. Express each force in Cartesian vector form and determine the magnitude and coordinate direction angles of the resultant force. 25% 0% 15% ⇒ The modulus of elasticity for mild steel is approximately equal to 10 kN/mm2 80 kN/mm2 100 kN/mm2 210 kN/mm2 ⇒ A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes.

Bending moment is INTERNAL, moment is EXTERNAL. BM for RHS of beam: M = Fr = -(6*3) = -18 kNm. Procedure to find BM at any cross-section in the beam: Cut beam thru that section, then add moments for the Q1: If distance a=7.8m and Force b=9.3kN, find the maximum bending moment.

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